What is the integral from 0 to 3.5 of 70x ?

The integral from 0 to 3.5 of 70x is 428.75

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integral from 0 to 3.5 of 70x

\int_{0}^{3.5} 70 x d x

428.75

Solution steps

\int_{0}^{3.5} 70 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 70 \cdot \int_{0}^{3.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{3.5}

= 70 [\frac{x ^{2}}{2}]_{0}^{3.5}

Simplify

= 70 [0.5 x^{2}]_{0}^{3.5}

Compute the boundaries:

6.125

= 70 \cdot 6.125

Simplify

= 428.75

\frac{d}{d x} (ln ∣ sin (x) ∣)

70 π t + 35 cos (\frac{- 2 π t - π}{2})

\int_{0}^{8} sin (x) d x

\int sin (3 x) cos (7 x) d x

x^{2} y^{^{''}} + 3 x y^{^{'}} - 24 y = 0, y (1) = 3, y^{^{'}} (1) = - 3

What is the integral from 0 to 3.5 of 70x ?
The integral from 0 to 3.5 of 70x is 428.75