What is the derivative of (x^3+3)(3x^2-4x+2) ?

The derivative of (x^3+3)(3x^2-4x+2) is 15x^4-16x^3+6x^2+18x-12

What is the first derivative of (x^3+3)(3x^2-4x+2) ?

The first derivative of (x^3+3)(3x^2-4x+2) is 15x^4-16x^3+6x^2+18x-12

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derivative of

(x^{3} + 3) (3 x^{2} - 4 x + 2)

15 x^{4} - 16 x^{3} + 6 x^{2} + 18 x - 12

Solution steps

\frac{d}{d x} ((x^{3} + 3) (3 x^{2} - 4 x + 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3} + 3, g = 3 x^{2} - 4 x + 2

= \frac{d}{d x} (x^{3} + 3) (3 x^{2} - 4 x + 2) + \frac{d}{d x} (3 x^{2} - 4 x + 2) (x^{3} + 3)

\frac{d}{d x} (x^{3} + 3) = 3 x^{2}

\frac{d}{d x} (3 x^{2} - 4 x + 2) = 6 x - 4

= 3 x^{2} (3 x^{2} - 4 x + 2) + (6 x - 4) (x^{3} + 3)

Simplify

3 x^{2} (3 x^{2} - 4 x + 2) + (6 x - 4) (x^{3} + 3) : 15 x^{4} - 16 x^{3} + 6 x^{2} + 18 x - 12

= 15 x^{4} - 16 x^{3} + 6 x^{2} + 18 x - 12

x \to 6 lim (\frac{x + 2}{( x + 6 )})

f (x) = 2 - 5 x^{2}, (3, - 43)

(csc (t) + cot (t))^{- 1}

\frac{d}{d x} ((x - 3) e^{x})

x \to 0 lim (\frac{( tan ( x ) )}{x})

What is the derivative of (x^3+3)(3x^2-4x+2) ?
The derivative of (x^3+3)(3x^2-4x+2) is 15x^4-16x^3+6x^2+18x-12
What is the first derivative of (x^3+3)(3x^2-4x+2) ?
The first derivative of (x^3+3)(3x^2-4x+2) is 15x^4-16x^3+6x^2+18x-12