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Popular >

y^'=(2xy-y^2)/(x^2)

Solution

y^{^{'}} = \frac{2 x y - y ^{2}}{x ^{2}}

Solution

y = \frac{x ^{2}}{x + c _{1}}

Solution steps

y^{'} (x) = \frac{2 x y - y ^{2}}{x ^{2}}

Solve Bernoulli ODE:

y = \frac{x ^{2}}{x + c _{1}}

y = \frac{x ^{2}}{x + c _{1}}

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\frac{d}{d y} (d y)

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\frac{d}{d x} ((ln (x))^{9})

integral of 9e^x

\int 9 e^{x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(2xy-y^2)/(x^2) ?
The solution for y^'=(2xy-y^2)/(x^2) is y=(x^2)/(x+c_{1)}