What is the integral of sin^2(x)cos(z) ?

The integral of sin^2(x)cos(z) is sin^2(x)sin(z)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sin^2(x)cos(z)

\int sin^{2} (x) cos (z) d z

sin^{2} (x) sin (z) + C

Solution steps

\int sin^{2} (x) cos (z) d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sin^{2} (x) \cdot \int cos (z) d z

Use the common integral:

\int cos (z) d z = sin (z)

= sin^{2} (x) sin (z)

Add a constant to the solution

= sin^{2} (x) sin (z) + C

\frac{d}{d x} (- 7 x^{2})

f (x) = (3 x - 1) (x + 2)

f (x) = 6 x^{3}

\frac{d}{d x} (cos (x^{2} + 3))

x \to 5 lim (- 12 x + 7)

What is the integral of sin^2(x)cos(z) ?
The integral of sin^2(x)cos(z) is sin^2(x)sin(z)+C