What is the solution for (xydy)/(dx)=2x^2+2y^2 ?

The solution for (xydy)/(dx)=2x^2+2y^2 is y=xsqrt(-2+c_{1)x^2},y=-xsqrt(-2+c_{1)x^2}

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(xydy)/(dx)=2x^2+2y^2

\frac{x y d y}{d x} = 2 x^{2} + 2 y^{2}

y = x - 2 + c_{1} x^{2}, y = - x - 2 + c_{1} x^{2}

Solution steps

\frac{x y d y}{d x} = 2 x^{2} + 2 y^{2}

Solve Bernoulli ODE:

y = x - 2 + c_{1} x^{2}, y = - x - 2 + c_{1} x^{2}

y = x - 2 + c_{1} x^{2}, y = - x - 2 + c_{1} x^{2}

\int 5 e^{x + 5} d x

2 t \cdot \frac{d y}{d t} + y = t

\int_{1}^{3} \frac{2}{x ^{2} + 2 x + 1} d x

f (x) = x^{2} + 5, at x = - 2

\frac{16}{4 + x ^{2}}, y = 1

What is the solution for (xydy)/(dx)=2x^2+2y^2 ?
The solution for (xydy)/(dx)=2x^2+2y^2 is y=xsqrt(-2+c_{1)x^2},y=-xsqrt(-2+c_{1)x^2}