What is the derivative of 12.18+3.1sin(0.017x-1.376) ?

The derivative of 12.18+3.1sin(0.017x-1.376) is 3.1(0.00329…cos(0.017x)+0.01667…sin(0.017x))

What is the first derivative of 12.18+3.1sin(0.017x-1.376) ?

The first derivative of 12.18+3.1sin(0.017x-1.376) is 3.1(0.00329…cos(0.017x)+0.01667…sin(0.017x))

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\frac{d}{d x} (12.18 + 3.1 sin (0.017 x - 1.376))

3.1 (0.00329 \dots cos (0.017 x) + 0.01667 \dots sin (0.017 x))

Solution steps

\frac{d}{d x} (12.18 + 3.1 sin (0.017 x - 1.376))

Simplify

12.18 + 3.1 sin (0.017 x - 1.376) : 12.18 + 3.1 (0.19356 \dots sin (0.017 x) - 0.98108 \dots cos (0.017 x))

= \frac{d}{d x} (12.18 + 3.1 (0.19356 \dots sin (0.017 x) - 0.98108 \dots cos (0.017 x)))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (12.18) + \frac{d}{d x} (3.1 (0.19356 \dots sin (0.017 x) - 0.98108 \dots cos (0.017 x)))

\frac{d}{d x} (12.18) = 0

\frac{d}{d x} (3.1 (0.19356 \dots sin (0.017 x) - 0.98108 \dots cos (0.017 x))) = 3.1 (0.00329 \dots cos (0.017 x) + 0.01667 \dots sin (0.017 x))

= 0 + 3.1 (0.00329 \dots cos (0.017 x) + 0.01667 \dots sin (0.017 x))

Simplify

= 3.1 (0.00329 \dots cos (0.017 x) + 0.01667 \dots sin (0.017 x))

\frac{d y}{d x} = (x - 4) e^{- 2 y}, y (4) = ln (4)

\frac{d}{d x} (ln (x^{2} y^{3}))

\int 2 y^{5} d y

n = 1 \sum \infty sin (2 n)

\int \frac{1}{x ( x ^{2} - 25 ) ^{\frac{3}{2}}} d x

What is the derivative of 12.18+3.1sin(0.017x-1.376) ?
The derivative of 12.18+3.1sin(0.017x-1.376) is 3.1(0.00329…cos(0.017x)+0.01667…sin(0.017x))
What is the first derivative of 12.18+3.1sin(0.017x-1.376) ?
The first derivative of 12.18+3.1sin(0.017x-1.376) is 3.1(0.00329…cos(0.017x)+0.01667…sin(0.017x))