What is the integral of (6/(x^3)) ?

The integral of (6/(x^3)) is -3/(x^2)+C

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integral of (6/(x^3))

\int (\frac{6}{x ^{3}}) d x

- \frac{3}{x ^{2}} + C

Solution steps

\int \frac{6}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= 6 (- \frac{1}{2 x ^{2}})

Simplify

6 (- \frac{1}{2 x ^{2}}) : - \frac{3}{x ^{2}}

= - \frac{3}{x ^{2}}

Add a constant to the solution

= - \frac{3}{x ^{2}} + C

\frac{\partial}{\partial y} (6 x y^{2} - 6 x^{2} y + 5 x y)

x^{4} - 5 x^{2} + 4

\frac{d}{d x} (e^{s i n (2 x)} + sin (e^{2 x}))

x \to 2 lim (\frac{1}{x ( x - 2 )})

\frac{\partial}{\partial x} (x^{2} y + x y^{3})