What is the derivative of x^2(x-3) ?

The derivative of x^2(x-3) is 3x^2-6x

What is the first derivative of x^2(x-3) ?

The first derivative of x^2(x-3) is 3x^2-6x

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\frac{d}{d x} (x^{2} (x - 3))

3 x^{2} - 6 x

Solution steps

\frac{d}{d x} (x^{2} (x - 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = x - 3

= \frac{d}{d x} (x^{2}) (x - 3) + \frac{d}{d x} (x - 3) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x - 3) = 1

= 2 x (x - 3) + 1 \cdot x^{2}

Simplify

2 x (x - 3) + 1 \cdot x^{2} : 3 x^{2} - 6 x

= 3 x^{2} - 6 x

f (y) = tan (y)

\int \frac{x ^{2} + x}{x} d x

f (x) = 72 x (6 x^{2} + 8)^{5}

\frac{\partial}{\partial x} (1 + x)

What is the derivative of x^2(x-3) ?
The derivative of x^2(x-3) is 3x^2-6x
What is the first derivative of x^2(x-3) ?
The first derivative of x^2(x-3) is 3x^2-6x