What is the integral of (2/(1+x^2)) ?

The integral of (2/(1+x^2)) is 2arctan(x)+C

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integral of (2/(1+x^2))

\int (\frac{2}{1 + x ^{2}}) d x

2 arctan (x) + C

Solution steps

\int \frac{2}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= 2 arctan (x)

Add a constant to the solution

= 2 arctan (x) + C

\frac{x ^{5} - 5}{x + 1}

x \to 4 lim (9 x + ∣ x - 4 ∣)

x d y + y d x = 3 d x

\frac{1 - cos ( x )}{sin ( x )}

What is the integral of (2/(1+x^2)) ?
The integral of (2/(1+x^2)) is 2arctan(x)+C