What is the derivative of 5x^4-60x^2+64 ?

The derivative of 5x^4-60x^2+64 is 20x^3-120x

What is the first derivative of 5x^4-60x^2+64 ?

The first derivative of 5x^4-60x^2+64 is 20x^3-120x

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\frac{d}{d x} (5 x^{4} - 60 x^{2} + 64)

20 x^{3} - 120 x

Solution steps

\frac{d}{d x} (5 x^{4} - 60 x^{2} + 64)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{4}) - \frac{d}{d x} (60 x^{2}) + \frac{d}{d x} (64)

\frac{d}{d x} (5 x^{4}) = 20 x^{3}

\frac{d}{d x} (60 x^{2}) = 120 x

\frac{d}{d x} (64) = 0

= 20 x^{3} - 120 x + 0

Simplify

= 20 x^{3} - 120 x

\int e^{x} x^{- 1} d x

\int_{2}^{\infty} e^{- 8 x} d x

y^{^{'}} = e^{x} y

\frac{d}{d x} (3 x - x^{3})

x \to - \infty lim (x - e^{x})

What is the derivative of 5x^4-60x^2+64 ?
The derivative of 5x^4-60x^2+64 is 20x^3-120x
What is the first derivative of 5x^4-60x^2+64 ?
The first derivative of 5x^4-60x^2+64 is 20x^3-120x