What is the derivative of (36/(x^2+2)) ?

The derivative of (36/(x^2+2)) is -(72x)/((x^2+2)^2)

What is the first derivative of (36/(x^2+2)) ?

The first derivative of (36/(x^2+2)) is -(72x)/((x^2+2)^2)

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\frac{d}{d x} (\frac{36}{x ^{2} + 2})

- \frac{72 x}{( x ^{2} + 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{36}{x ^{2} + 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 36 \frac{d}{d x} (\frac{1}{x ^{2} + 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 36 \frac{d}{d x} ((x^{2} + 2)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} + 2 ) ^{2}} \frac{d}{d x} (x^{2} + 2)

= - \frac{1}{( x ^{2} + 2 ) ^{2}} \frac{d}{d x} (x^{2} + 2)

\frac{d}{d x} (x^{2} + 2) = 2 x

= 36 (- \frac{1}{( x ^{2} + 2 ) ^{2}} \cdot 2 x)

Simplify

36 (- \frac{1}{( x ^{2} + 2 ) ^{2}} \cdot 2 x) : - \frac{72 x}{( x ^{2} + 2 ) ^{2}}

= - \frac{72 x}{( x ^{2} + 2 ) ^{2}}

\int - \frac{2 ln ( x )}{x} d x

\int tan^{3} (2 x) sec (2 x) d x

\frac{d}{d x} ((1 + \frac{1}{x})^{x})

\frac{d y}{d x} + (3 x y^{3}) = 0, y (0) = 1

\frac{d}{d x} (\frac{3}{6 x + 3})

What is the derivative of (36/(x^2+2)) ?
The derivative of (36/(x^2+2)) is -(72x)/((x^2+2)^2)
What is the first derivative of (36/(x^2+2)) ?
The first derivative of (36/(x^2+2)) is -(72x)/((x^2+2)^2)