What is the derivative of (1+x^3^{2020}) ?

The derivative of (1+x^3^{2020}) is 6060x^2(1+x^3)^{2019}

What is the first derivative of (1+x^3^{2020}) ?

The first derivative of (1+x^3^{2020}) is 6060x^2(1+x^3)^{2019}

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\frac{d}{d x} ((1 + x^{3})^{2020})

6060 x^{2} (1 + x^{3})^{2019}

Solution steps

\frac{d}{d x} ((1 + x^{3})^{2020})

Apply the chain rule:

2020 (1 + x^{3})^{2019} \frac{d}{d x} (1 + x^{3})

= 2020 (1 + x^{3})^{2019} \frac{d}{d x} (1 + x^{3})

\frac{d}{d x} (1 + x^{3}) = 3 x^{2}

= 2020 (1 + x^{3})^{2019} \cdot 3 x^{2}

Simplify

= 6060 x^{2} (1 + x^{3})^{2019}

\frac{d}{d x} (4 e^{- x^{2}})

(8, 8), (4, 6)

e^{2 x} + 2 e^{2 x} x

\frac{d y}{d t} + a y = b

2 x

What is the derivative of (1+x^3^{2020}) ?
The derivative of (1+x^3^{2020}) is 6060x^2(1+x^3)^{2019}
What is the first derivative of (1+x^3^{2020}) ?
The first derivative of (1+x^3^{2020}) is 6060x^2(1+x^3)^{2019}