What is (\partial)/(\partial x)(6x^{-3}-8x^{-5}) ?

The answer to (\partial)/(\partial x)(6x^{-3}-8x^{-5}) is -(18)/(x^4)+(40)/(x^6)

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(\partial)/(\partial x)(6x^{-3}-8x^{-5})

\frac{\partial}{\partial x} (6 x^{- 3} - 8 x^{- 5})

- \frac{18}{x ^{4}} + \frac{40}{x ^{6}}

Solution steps

\frac{\partial}{\partial x} (6 x^{- 3} - 8 x^{- 5})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (6 x^{- 3}) - \frac{\partial}{\partial x} (8 x^{- 5})

\frac{\partial}{\partial x} (6 x^{- 3}) = - \frac{18}{x ^{4}}

\frac{\partial}{\partial x} (8 x^{- 5}) = - \frac{40}{x ^{6}}

= - \frac{18}{x ^{4}} - (- \frac{40}{x ^{6}})

Simplify

= - \frac{18}{x ^{4}} + \frac{40}{x ^{6}}

\frac{d}{d x} (500 x - \frac{x ^{2}}{ln ( x + 300 )})

\frac{d}{d x} ((3 x^{2} - 6 x + 10) (x^{3}))

y^{^{''}} + 2 y^{^{'}} + 5 y = e^{(- x)} sec (2 x)

4 e^{5 x}

What is (\partial)/(\partial x)(6x^{-3}-8x^{-5}) ?
The answer to (\partial)/(\partial x)(6x^{-3}-8x^{-5}) is -(18)/(x^4)+(40)/(x^6)