What is the solution for (dy)/(dx)=e^{2x-3y} ?

The solution for (dy)/(dx)=e^{2x-3y} is y=(ln(3/2 e^{2x}+c_{1}))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=e^{2x-3y}

\frac{d y}{d x} = e^{2 x - 3 y}

y = \frac{ln ( \frac{3}{2} e ^{2 x} + c _{1} )}{3}

Solution steps

\frac{d y}{d x} = e^{2 x - 3 y}

Solve separable ODE:

y = \frac{ln ( \frac{3}{2} e ^{2 x} + c _{1} )}{3}

y = \frac{ln ( \frac{3}{2} e ^{2 x} + c _{1} )}{3}

\frac{\partial}{\partial x} (7 x cos (x) cos (y))

\frac{d y}{d t} = 8 - \frac{y}{200 + 3 t}

7 e^{x} cos (x)

f (x) = - 2 x e^{x^{2}}, at x = 2

n = 4 \sum \infty \frac{x ^{n}}{n ^{5}}

What is the solution for (dy)/(dx)=e^{2x-3y} ?
The solution for (dy)/(dx)=e^{2x-3y} is y=(ln(3/2 e^{2x}+c_{1}))/3