What is the integral from 0 to pi of cos(3x) ?

The integral from 0 to pi of cos(3x) is 0

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integral from 0 to pi of cos(3x)

\int_{0}^{π} cos (3 x) d x

0

Solution steps

\int_{0}^{π} cos (3 x) d x

Apply u-substitution

: \int_{0}^{3 π} cos (u) \frac{1}{3} d u

= \int_{0}^{3 π} cos (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{0}^{3 π} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{3} [sin (u)]_{0}^{3 π}

Compute the boundaries:

0

= \frac{1}{3} \cdot 0

Simplify

= 0

y^{^{''}} + 4 y^{^{'}} + 13 y = 0, y (0) = 7, y^{^{'}} (0) = 7

f (x) = (3 x - 4)

\frac{d}{d x} (50 x)

ln (1 + x^{2})

f (x) = e^{2} + ln (7)

What is the integral from 0 to pi of cos(3x) ?
The integral from 0 to pi of cos(3x) is 0