What is the first derivative of 4x^2+5 ?

The first derivative of 4x^2+5 is 8x

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derivative of 4x^2+5

derivative of

4 x^{2} + 5

8 x

Solution steps

\frac{d}{d x} (4 x^{2} + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (5)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (5) = 0

= 8 x + 0

Simplify

= 8 x

\int \frac{3 x ^{2} + 2 x}{x ^{2} - 1} d x

\frac{d}{d x} (e^{x} + ln (x))

y^{^{''}} - 4 y^{^{'}} = 6 t

\frac{7 s ^{3} - 9 s + 1}{3 s ^{5}}

\int \frac{3}{x ( x ^{4} + 1 )} d x