What is the solution for (11+x^2)y^'-2xy=0 ?

The solution for (11+x^2)y^'-2xy=0 is y=11e^{c_{1}}+e^{c_{1}}x^2

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(11+x^2)y^'-2xy=0

(11 + x^{2}) y^{^{'}} - 2 x y = 0

y = 11 e^{c_{1}} + e^{c_{1}} x^{2}

Solution steps

(11 + x^{2}) y^{'} (x) - 2 x y = 0

Solve separable ODE:

y = 11 e^{c_{1}} + e^{c_{1}} x^{2}

y = 11 e^{c_{1}} + e^{c_{1}} x^{2}

\int \frac{1}{8 x ^{2} - 16 x + 64} d x

\frac{\partial}{\partial t} (s e^{t})

\frac{\partial}{\partial t} (s sin (t))

x \to - 2 lim (\frac{5}{x + 2})

f (x) = 2^{3 x^{2} - 6}

What is the solution for (11+x^2)y^'-2xy=0 ?
The solution for (11+x^2)y^'-2xy=0 is y=11e^{c_{1}}+e^{c_{1}}x^2