What is the tangent of y=x^2-7,(3,2) ?

The tangent of y=x^2-7,(3,2) is y=6x-16

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tangent of y=x^2-7,(3,2)

tangent of

y = x^{2} - 7, (3, 2)

y = 6 x - 16

Solution steps

Find the slope of

y = x^{2} - 7 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} - 7

(3, 2) : m = 6

Find the line with slope m=

6

and passing through

(3, 2) : y = 6 x - 16

y = 6 x - 16

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