What is the tangent of 1/x ,\at x=4 ?

The tangent of 1/x ,\at x=4 is y=-1/16 x+1/2

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tangent of 1/x ,\at x=4

tangent of

\frac{1}{x}, at x = 4

y = - \frac{1}{16} x + \frac{1}{2}

Solution steps

Find the tangent point:

(4, \frac{1}{4})

Find the slope of

y = \frac{1}{x} : \frac{d y}{d x} = - \frac{1}{x ^{2}}

Compute the slope of

y = \frac{1}{x}

x = 4 : m = - \frac{1}{16}

Find the line with slope m=

- \frac{1}{16}

and passing through

(4, \frac{1}{4}) : y = - \frac{1}{16} x + \frac{1}{2}

y = - \frac{1}{16} x + \frac{1}{2}

\frac{d}{d x} (cot (9) (1 - 2 x^{2}))

n \to 0 lim (n sin (\frac{1}{n}))

\int ln (x^{2} - 4) d x

n = 0 \sum \infty \frac{n ^{7}}{7 ^{n}}

\frac{d}{d x} ((4 x^{2} + x) (x - x^{2}))

What is the tangent of 1/x ,\at x=4 ?
The tangent of 1/x ,\at x=4 is y=-1/16 x+1/2