What is the integral of x/(sqrt(x^2)) ?

The integral of x/(sqrt(x^2)) is x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x/(sqrt(x^2))

\int \frac{x}{x ^{2}} d x

x + C

Solution steps

\int \frac{x}{x ^{2}} d x

x^{2} = (x),

assuming

x \geq 0

= \int \frac{x}{x} d x

Simplify

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C

x^{2} y^{^{'}} + x y = 3 y^{3}

x \to 4 lim (\frac{f ( x )}{g ( x )})

x \to 0 lim (x e^{- x^{2}})

\int 54 sec^{4} (x) d x

\int \frac{3}{16} y^{2} d y