What is the limit as x approaches infinity of 1+6/x ?

The limit as x approaches infinity of 1+6/x is 1

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limit as x approaches infinity of 1+6/x

x \to \infty lim (1 + \frac{6}{x})

1

Solution steps

x \to \infty lim (1 + \frac{6}{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (1) + x \to \infty lim (\frac{6}{x})

x \to \infty lim (1) = 1

x \to \infty lim (\frac{6}{x}) = 0

= 1 + 0

Simplify

= 1

\int_{0}^{\frac{π}{6}} sin (2 x) d x

\int 3 x^{2} sin (3 x) d x

f (x) = 3^{x^{2} - 3}

\int \frac{1}{x ^{2} + 2 x + 2} d x

y = (3 x - x^{2}) (3 - x - x^{2})

What is the limit as x approaches infinity of 1+6/x ?
The limit as x approaches infinity of 1+6/x is 1