What is the integral from 1 to 9 of 1/(sqrt(x)) ?

The integral from 1 to 9 of 1/(sqrt(x)) is 4

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integral from 1 to 9 of 1/(sqrt(x))

\int_{1}^{9} \frac{1}{x} d x

4

Solution steps

\int_{1}^{9} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{1}^{9}

= [2 x^{\frac{1}{2}}]_{1}^{9}

Apply radical rule:

= [2 x]_{1}^{9}

Compute the boundaries:

4

= 4

x \frac{d y}{d x} + (11 + x) y = e^{- x}

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\int \frac{1}{1 + x ^{4}} d x

\int_{0}^{2} x^{5} e^{x^{3}} d x

What is the integral from 1 to 9 of 1/(sqrt(x)) ?
The integral from 1 to 9 of 1/(sqrt(x)) is 4