What is the sum from y=0 to infinity of 2^{-2-y+x} ?

The sum from y=0 to infinity of 2^{-2-y+x} is converges

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sum from y=0 to infinity of 2^{-2-y+x}

y = 0 \sum \infty 2^{- 2 - y + x}

converges

Solution steps

n = 0 \sum \infty 2^{- 2 - n + x}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial y} (x 1 + y^{5})

\int t e^{- a t} d t

f (t) = t sin (t) + cos (t)

\frac{\partial}{\partial x} (e^{t^{2}})

y = 2 x^{2}, y = 0, [5, 50]

What is the sum from y=0 to infinity of 2^{-2-y+x} ?
The sum from y=0 to infinity of 2^{-2-y+x} is converges