What is (\partial)/(\partial x)(2y-2cos(x)) ?

The answer to (\partial)/(\partial x)(2y-2cos(x)) is 2sin(x)

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(\partial)/(\partial x)(2y-2cos(x))

\frac{\partial}{\partial x} (2 y - 2 cos (x))

2 sin (x)

Solution steps

\frac{\partial}{\partial x} (2 y - 2 cos (x))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (2 cos (x))

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (2 cos (x)) = - 2 sin (x)

= 0 - (- 2 sin (x))

Simplify

= 2 sin (x)

6 t^{2} y^{^{''}} - 12 y = 14 t^{2} - 1

\int \frac{x}{( x + 1 ) ( x + 2 ) ( x + 3 )} d x

\frac{d}{d x} (\frac{e ^{x}}{3 x})

\frac{\partial}{\partial x} (ln (x + y) + x cos (y))

\int_{0}^{3} \frac{7 t}{( t - 4 ) ^{2}} d t

What is (\partial)/(\partial x)(2y-2cos(x)) ?
The answer to (\partial)/(\partial x)(2y-2cos(x)) is 2sin(x)