What is the derivative of 7x^e+e^{9x} ?

The derivative of 7x^e+e^{9x} is 7ex^{e-1}+e^{9x}*9

What is the first derivative of 7x^e+e^{9x} ?

The first derivative of 7x^e+e^{9x} is 7ex^{e-1}+e^{9x}*9

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derivative of

7 x^{e} + e^{9 x}

7 e x^{e - 1} + e^{9 x} \cdot 9

Solution steps

\frac{d}{d x} (7 x^{e} + e^{9 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (7 x^{e}) + \frac{d}{d x} (e^{9 x})

\frac{d}{d x} (7 x^{e}) = 7 e x^{e - 1}

\frac{d}{d x} (e^{9 x}) = e^{9 x} \cdot 9

= 7 e x^{e - 1} + e^{9 x} \cdot 9

f (x) = \frac{x ^{2}}{5 + x}

\int (a^{2} - x^{2})^{\frac{5}{2}} d x

\int 4 x^{3} - 10 x d x

\int \frac{4 t ^{3} - t ^{2} + 16 t}{t ^{2} + 4} d t

n = 1 \sum \infty \frac{n}{n ^{2} + 3}

What is the derivative of 7x^e+e^{9x} ?
The derivative of 7x^e+e^{9x} is 7ex^{e-1}+e^{9x}*9
What is the first derivative of 7x^e+e^{9x} ?
The first derivative of 7x^e+e^{9x} is 7ex^{e-1}+e^{9x}*9