What is the derivative of f(x)=csc^7(2x^pi+pi^3) ?

The derivative of f(x)=csc^7(2x^pi+pi^3) is -14pix^{pi-1}csc^7(2x^pi+pi^3)cot(2x^pi+pi^3)

What is the first derivative of f(x)=csc^7(2x^pi+pi^3) ?

The first derivative of f(x)=csc^7(2x^pi+pi^3) is -14pix^{pi-1}csc^7(2x^pi+pi^3)cot(2x^pi+pi^3)

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derivative of

f (x) = csc^{7} (2 x^{π} + π^{3})

- 14 π x^{π - 1} csc^{7} (2 x^{π} + π^{3}) cot (2 x^{π} + π^{3})

Solution steps

\frac{d}{d x} (csc^{7} (2 x^{π} + π^{3}))

Apply the chain rule:

7 (csc (2 x^{π} + π^{3}))^{6} \frac{d}{d x} (csc (2 x^{π} + π^{3}))

= 7 (csc (2 x^{π} + π^{3}))^{6} \frac{d}{d x} (csc (2 x^{π} + π^{3}))

\frac{d}{d x} (csc (2 x^{π} + π^{3})) = - cot (2 x^{π} + π^{3}) csc (2 x^{π} + π^{3}) \cdot 2 π x^{π - 1}

= 7 (csc (2 x^{π} + π^{3}))^{6} (- cot (2 x^{π} + π^{3}) csc (2 x^{π} + π^{3}) \cdot 2 π x^{π - 1})

Simplify

7 csc^{6} (2 x^{π} + π^{3}) (- cot (2 x^{π} + π^{3}) csc (2 x^{π} + π^{3}) \cdot 2 π x^{π - 1}) : - 14 π x^{π - 1} csc^{7} (2 x^{π} + π^{3}) cot (2 x^{π} + π^{3})

= - 14 π x^{π - 1} csc^{7} (2 x^{π} + π^{3}) cot (2 x^{π} + π^{3})

y = x^{2} - 7 x + 7, (4, 0)

y^{^{''}} - 9 y = 0

\frac{d}{d x} (\frac{2 x ^{2} + 4 x + 2}{x})

\frac{d y}{d x} = \frac{- y ^{2}}{1 + y ^{2}} e^{- x}

x \to 2 - lim (\frac{x ^{3} + 1}{x - 2})

What is the derivative of f(x)=csc^7(2x^pi+pi^3) ?
The derivative of f(x)=csc^7(2x^pi+pi^3) is -14pix^{pi-1}csc^7(2x^pi+pi^3)cot(2x^pi+pi^3)
What is the first derivative of f(x)=csc^7(2x^pi+pi^3) ?
The first derivative of f(x)=csc^7(2x^pi+pi^3) is -14pix^{pi-1}csc^7(2x^pi+pi^3)cot(2x^pi+pi^3)