What is the d/(dt)(6cos(t)) ?

The d/(dt)(6cos(t)) is -6sin(t)

What is the first d/(dt)(6cos(t)) ?

The first d/(dt)(6cos(t)) is -6sin(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (6 cos (t))

- 6 sin (t)

Solution steps

\frac{d}{d t} (6 cos (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d t} (cos (t))

Apply the common derivative:

\frac{d}{d t} (cos (t)) = - sin (t)

= 6 (- sin (t))

Simplify

= - 6 sin (t)

\int_{1}^{2} x^{- 2} d x

y = \frac{16}{x ^{2} - 6 x - 55}, x = - 3, x = 3

\int \frac{x ^{2} + 132 x + 132}{x ^{3} - 4 x} d x

\int \frac{e ^{x}}{e ^{2 x} - e ^{x}} d x

\frac{\partial}{\partial z} (ln (x))