What is the solution for (3t+6y+3)=(dy)/(dt) ?

The solution for (3t+6y+3)=(dy)/(dt) is y=-t/2-7/12+c_{1}e^{6t}

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(3t+6y+3)=(dy)/(dt)

(3 t + 6 y + 3) = \frac{d y}{d t}

y = - \frac{t}{2} - \frac{7}{12} + c_{1} e^{6 t}

Solution steps

(3 t + 6 y + 3) = \frac{d y}{d t}

Solve linear ODE:

y = - \frac{t}{2} - \frac{7}{12} + c_{1} e^{6 t}

y = - \frac{t}{2} - \frac{7}{12} + c_{1} e^{6 t}

x

\int 1 - x d x

y = - x^{3}, (- 2, 8)

x \to + 0 lim (arctan (x))

What is the solution for (3t+6y+3)=(dy)/(dt) ?
The solution for (3t+6y+3)=(dy)/(dt) is y=-t/2-7/12+c_{1}e^{6t}