What is the solution for xy^'+2y=(4e^{3x})/x ?

The solution for xy^'+2y=(4e^{3x})/x is y=(4e^{3x})/(3x^2)+(c_{1})/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

xy^'+2y=(4e^{3x})/x

x y^{^{'}} + 2 y = \frac{4 e ^{3 x}}{x}

y = \frac{4 e ^{3 x}}{3 x ^{2}} + \frac{c _{1}}{x ^{2}}

Solution steps

x y^{'} (x) + 2 y = \frac{4 e ^{3 x}}{x}

Solve linear ODE:

y = \frac{4 e ^{3 x}}{3 x ^{2}} + \frac{c _{1}}{x ^{2}}

y = \frac{4 e ^{3 x}}{3 x ^{2}} + \frac{c _{1}}{x ^{2}}

f (x) = 2 x^{3} - 21 x^{2} + 72 x - 5

\frac{\partial}{\partial x} (e^{2 x - y})

x \to 0 lim (\frac{x - 14}{x - 2})

x \to 0 + lim (\frac{1}{x ^{2}})

\int - 30 t^{\frac{2}{3}} d t

What is the solution for xy^'+2y=(4e^{3x})/x ?
The solution for xy^'+2y=(4e^{3x})/x is y=(4e^{3x})/(3x^2)+(c_{1})/(x^2)