What is the limit as x approaches 4 of (3x^2-8x-16)/(2x^2-9x+4) ?

The limit as x approaches 4 of (3x^2-8x-16)/(2x^2-9x+4) is 16/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 4 of (3x^2-8x-16)/(2x^2-9x+4)

x \to 4 lim (\frac{3 x ^{2} - 8 x - 16}{2 x ^{2} - 9 x + 4})

\frac{16}{7}

Decimal Notation

2.28571 \dots

Solution steps

x \to 4 lim (\frac{3 x ^{2} - 8 x - 16}{2 x ^{2} - 9 x + 4})

Simplify

\frac{3 x ^{2} - 8 x - 16}{2 x ^{2} - 9 x + 4} : \frac{3 x + 4}{2 x - 1}

= x \to 4 lim (\frac{3 x + 4}{2 x - 1})

Plug in the value

x = 4

= \frac{3 \cdot 4 + 4}{2 \cdot 4 - 1}

Simplify

= \frac{16}{7}

\frac{\partial}{\partial x} (e^{x + y} (x - 1) (y - 2))

\frac{s + 1}{( s + 1 ) ^{2} + 4}

\int x^{2} 4 x + 8 d x

y = x^{2}, y = 4 + x

\int x (x - 3)^{2} + 4^{2} d x

What is the limit as x approaches 4 of (3x^2-8x-16)/(2x^2-9x+4) ?
The limit as x approaches 4 of (3x^2-8x-16)/(2x^2-9x+4) is 16/7