What is the derivative of 7\sqrt[4]{-v} ?

The derivative of 7\sqrt[4]{-v} is -7/(4(-v)^{3/4)}

What is the first derivative of 7\sqrt[4]{-v} ?

The first derivative of 7\sqrt[4]{-v} is -7/(4(-v)^{3/4)}

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derivative of

- \frac{7}{4 ( - v ) ^{\frac{3}{4}}}

Solution steps

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

Apply the chain rule:

\frac{1}{4 ( - v ) ^{\frac{3}{4}}} \frac{d}{d v} (- v)

= \frac{1}{4 ( - v ) ^{\frac{3}{4}}} \frac{d}{d v} (- v)

\frac{d}{d v} (- v) = - 1

= 7 \cdot \frac{1}{4 ( - v ) ^{\frac{3}{4}}} (- 1)

Simplify

7 \cdot \frac{1}{4 ( - v ) ^{\frac{3}{4}}} (- 1) : - \frac{7}{4 ( - v ) ^{\frac{3}{4}}}

= - \frac{7}{4 ( - v ) ^{\frac{3}{4}}}

sin (t) = y^{^{'}} + y

n = 1 \sum \infty \frac{- 1}{n + 1}

\int (1 - 6 x) e^{3 x - 9 x^{2}} d x

n \to \infty lim (7^{n})

\int_{0}^{11} 2 π y (121 - y^{2}) d y

What is the derivative of 7\sqrt[4]{-v} ?
The derivative of 7\sqrt[4]{-v} is -7/(4(-v)^{3/4)}
What is the first derivative of 7\sqrt[4]{-v} ?
The first derivative of 7\sqrt[4]{-v} is -7/(4(-v)^{3/4)}