What is laplacetransform f(t)=6t^3e^{-2t} ?

The answer to laplacetransform f(t)=6t^3e^{-2t} is (36)/((s+2)^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform f(t)=6t^3e^{-2t}

laplace transform

f (t) = 6 t^{3} e^{- 2 t}

\frac{36}{( s + 2 ) ^{4}}

Solution steps

L {6 e^{- 2 t} t^{3}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 6 L {t^{3} e^{- 2 t}}

L {t^{3} e^{- 2 t}} : \frac{6}{( s + 2 ) ^{4}}

= 6 \cdot \frac{6}{( s + 2 ) ^{4}}

Refine

6 \frac{6}{( s + 2 ) ^{4}} : \frac{36}{( s + 2 ) ^{4}}

= \frac{36}{( s + 2 ) ^{4}}

x \to 4 lim (\frac{x ^{2} - 9}{x - 3})

\frac{sec ^{2} ( x )}{2}, 2 cos^{2} (x)

x \to 2 lim (4 x^{2} - 11 x - 2)

\int_{0}^{1} \frac{1}{( 16 + x ^{2} ) ^{2}} d x

x \to 0 lim (\frac{1}{5 + 5})

What is laplacetransform f(t)=6t^3e^{-2t} ?
The answer to laplacetransform f(t)=6t^3e^{-2t} is (36)/((s+2)^4)