What is the derivative of (3x^4+4)^2 ?

The derivative of (3x^4+4)^2 is 24x^3(3x^4+4)

What is the first derivative of (3x^4+4)^2 ?

The first derivative of (3x^4+4)^2 is 24x^3(3x^4+4)

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derivative of

(3 x^{4} + 4)^{2}

24 x^{3} (3 x^{4} + 4)

Solution steps

\frac{d}{d x} ((3 x^{4} + 4)^{2})

Apply the chain rule:

2 (3 x^{4} + 4) \frac{d}{d x} (3 x^{4} + 4)

= 2 (3 x^{4} + 4) \frac{d}{d x} (3 x^{4} + 4)

\frac{d}{d x} (3 x^{4} + 4) = 12 x^{3}

= 2 (3 x^{4} + 4) \cdot 12 x^{3}

Simplify

= 24 x^{3} (3 x^{4} + 4)

y^{^{''}} + 4 y^{^{'}} + 3 y = 6 e^{- x}

\int \frac{1}{a x + b} d x

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + y = \frac{e ^{x}}{x ^{2} + 1}

y = ln (x^{2} + y^{2})

\frac{\partial}{\partial y} (e^{x^{2} - y^{2}})

What is the derivative of (3x^4+4)^2 ?
The derivative of (3x^4+4)^2 is 24x^3(3x^4+4)
What is the first derivative of (3x^4+4)^2 ?
The first derivative of (3x^4+4)^2 is 24x^3(3x^4+4)