What is the derivative of 1.5(1/3+x/2-(x^3/6)) ?

The derivative of 1.5(1/3+x/2-(x^3/6)) is 1.5(-0.5x^2+0.5)

What is the first derivative of 1.5(1/3+x/2-(x^3/6)) ?

The first derivative of 1.5(1/3+x/2-(x^3/6)) is 1.5(-0.5x^2+0.5)

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\frac{d}{d x} (1.5 (\frac{1}{3} + \frac{x}{2} - \frac{x ^{3}}{6}))

1.5 (- 0.5 x^{2} + 0.5)

Solution steps

\frac{d}{d x} (1.5 (\frac{1}{3} + \frac{x}{2} - \frac{x ^{3}}{6}))

Simplify

1.5 (\frac{1}{3} + \frac{x}{2} - \frac{x ^{3}}{6}) : 1.5 (0.33333 \dots + 0.5 x - 0.16666 \dots x^{3})

= \frac{d}{d x} (1.5 (0.33333 \dots + 0.5 x - 0.16666 \dots x^{3}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 1.5 \frac{d}{d x} (0.33333 \dots + 0.5 x - 0.16666 \dots x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 1.5 (\frac{d}{d x} (0.33333 \dots) + \frac{d}{d x} (0.5 x) - \frac{d}{d x} (0.16666 \dots x^{3}))

\frac{d}{d x} (0.33333 \dots) = 0

\frac{d}{d x} (0.5 x) = 0.5

\frac{d}{d x} (0.16666 \dots x^{3}) = 0.5 x^{2}

= 1.5 (0 + 0.5 - 0.5 x^{2})

Simplify

= 1.5 (- 0.5 x^{2} + 0.5)

\int \frac{1}{- x ^{2} - 2 x 8} d x

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What is the derivative of 1.5(1/3+x/2-(x^3/6)) ?
The derivative of 1.5(1/3+x/2-(x^3/6)) is 1.5(-0.5x^2+0.5)
What is the first derivative of 1.5(1/3+x/2-(x^3/6)) ?
The first derivative of 1.5(1/3+x/2-(x^3/6)) is 1.5(-0.5x^2+0.5)