What is the limit as x approaches 0+of (1/5)^{1/x} ?

The limit as x approaches 0+of (1/5)^{1/x} is 0

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limit as x approaches 0+of (1/5)^{1/x}

x \to 0 + lim ((\frac{1}{5})^{\frac{1}{x}})

0

Solution steps

x \to 0 + lim ((\frac{1}{5})^{\frac{1}{x}})

Apply exponent rules

= x \to 0 + lim (e^{\frac{1}{x} l n (\frac{1}{5})})

Apply the Limit Chain Rule:

0

= 0

\frac{\partial}{\partial x} (x^{\frac{1}{2}} y^{\frac{1}{2}} z)

\int_{0}^{6} 1 + x d x

x \to 3 + lim (\frac{x + 9}{x - 3})

\int \frac{ln ( x + 8 )}{x + 8} d x

\frac{\partial}{\partial x} (\frac{2 x - 4 y}{2 x + 4 y})

What is the limit as x approaches 0+of (1/5)^{1/x} ?
The limit as x approaches 0+of (1/5)^{1/x} is 0