What is the derivative of ln(14-9x^2+2x^4) ?

The derivative of ln(14-9x^2+2x^4) is (8x^3-18x)/(14-9x^2+2x^4)

What is the first derivative of ln(14-9x^2+2x^4) ?

The first derivative of ln(14-9x^2+2x^4) is (8x^3-18x)/(14-9x^2+2x^4)

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derivative of

ln (14 - 9 x^{2} + 2 x^{4})

\frac{8 x ^{3} - 18 x}{14 - 9 x ^{2} + 2 x ^{4}}

Solution steps

\frac{d}{d x} (ln (14 - 9 x^{2} + 2 x^{4}))

Apply the chain rule:

\frac{1}{14 - 9 x ^{2} + 2 x ^{4}} \frac{d}{d x} (14 - 9 x^{2} + 2 x^{4})

= \frac{1}{14 - 9 x ^{2} + 2 x ^{4}} \frac{d}{d x} (14 - 9 x^{2} + 2 x^{4})

\frac{d}{d x} (14 - 9 x^{2} + 2 x^{4}) = 8 x^{3} - 18 x

= \frac{1}{14 - 9 x ^{2} + 2 x ^{4}} (8 x^{3} - 18 x)

Simplify

\frac{1}{14 - 9 x ^{2} + 2 x ^{4}} (8 x^{3} - 18 x) : \frac{8 x ^{3} - 18 x}{14 - 9 x ^{2} + 2 x ^{4}}

= \frac{8 x ^{3} - 18 x}{14 - 9 x ^{2} + 2 x ^{4}}

\frac{d}{d x} (\frac{2 x ^{2} + 4 x}{2 + x ^{2}})

\int cos (t) sin (t) d t

\frac{2 x ^{2} - 5 x + 5}{x - 2}

\frac{d}{d x} (f (x) sin (x))

x \to 0 lim (\frac{x}{8 x ^{2} - x})

What is the derivative of ln(14-9x^2+2x^4) ?
The derivative of ln(14-9x^2+2x^4) is (8x^3-18x)/(14-9x^2+2x^4)
What is the first derivative of ln(14-9x^2+2x^4) ?
The first derivative of ln(14-9x^2+2x^4) is (8x^3-18x)/(14-9x^2+2x^4)