What is the sum from n=0 to infinity of (1/9)^n ?

The sum from n=0 to infinity of (1/9)^n is 9/8

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sum from n=0 to infinity of (1/9)^n

n = 0 \sum \infty (\frac{1}{9})^{n}

\frac{9}{8}

Solution steps

n = 0 \sum \infty (\frac{1}{9})^{n}

Apply Series Geometric Test:

\frac{9}{8}

= \frac{9}{8}

\frac{d}{d x} (x + \frac{3}{x} + 5)

\frac{\partial}{\partial x} (tan (\frac{x}{2}))

y^{^{'''}} + 4 y^{^{''}} - 35 y^{^{'}} - 150 y = 0

\int \frac{1}{x ^{\frac{1}{3}} ( x ^{\frac{2}{3}} + 4 )} d x

What is the sum from n=0 to infinity of (1/9)^n ?
The sum from n=0 to infinity of (1/9)^n is 9/8