What is maclaurin 6sin(x) ?

The answer to maclaurin 6sin(x) is 6x-x^3+1/20 x^5-1/840 x^7+1/60480 x^9+\ldots

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maclaurin 6sin(x)

maclaurin

6 sin (x)

6 x - x^{3} + \frac{1}{20} x^{5} - \frac{1}{840} x^{7} + \frac{1}{60480} x^{9} + \dots

Solution steps

Apply the Maclaurin Formula

= 0 + \frac{\frac{d}{d x} ( 6 sin ( x ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 6 sin ( x ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 6 sin ( x ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{6}{1 !} x + \frac{0}{2 !} x^{2} + \frac{- 6}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{6}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{- 6}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{6}{9 !} x^{9} + \dots

Refine

= 6 x - x^{3} + \frac{1}{20} x^{5} - \frac{1}{840} x^{7} + \frac{1}{60480} x^{9} + \dots

\frac{\partial}{\partial x} (x^{3} y e^{x y})

\frac{\partial}{\partial x} (x^{2} - x + 2 y^{2} + yz - 10)

\frac{\partial}{\partial x} (x (y)^{\frac{1}{2}})

y = \frac{x ^{5}}{10} + \frac{1}{6 x ^{3}}

n = 1 \sum \infty \frac{n}{( n + 1 ) !}

What is maclaurin 6sin(x) ?
The answer to maclaurin 6sin(x) is 6x-x^3+1/20 x^5-1/840 x^7+1/60480 x^9+\ldots