What is the integral of sin(4t) ?

The integral of sin(4t) is -1/4 cos(4t)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of sin(4t)

\int sin (4 t) d t

- \frac{1}{4} cos (4 t) + C

Solution steps

\int sin (4 t) d t

Apply u-substitution

: \int sin (u) \frac{1}{4} d u

= \int sin (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{4} (- cos (u))

Substitute back

u = 4 t

= \frac{1}{4} (- cos (4 t))

Simplify

= - \frac{1}{4} cos (4 t)

Add a constant to the solution

= - \frac{1}{4} cos (4 t) + C

\int sin (x) sin (2 x) d x

y^{^{'}} = 4 x + y, y (0) = 1

\int_{0}^{6} 6 x - (3 x - 12) d x

\int_{0}^{\infty} \frac{1}{7 + x} d x

\int e^{2} x d x