What is the solution for y^'= 2/3 xsqrt(1-9y^2) ?

The solution for y^'= 2/3 xsqrt(1-9y^2) is y=(sin(x^2+c_{1}))/3

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y^'= 2/3 xsqrt(1-9y^2)

y^{^{'}} = \frac{2}{3} x 1 - 9 y^{2}

y = \frac{sin ( x ^{2} + c _{1} )}{3}

Solution steps

y^{'} (x) = \frac{2}{3} x 1 - 9 y^{2}

Solve separable ODE:

y = \frac{sin ( x ^{2} + c _{1} )}{3}

y = \frac{sin ( x ^{2} + c _{1} )}{3}

f (x) = x^{2} + 2, at x = 3

\frac{d}{d x} (4 x arcsin (x))

\frac{d}{d x} (\frac{ln ( 1 )}{x})

\frac{\partial}{\partial x} (2 e^{y} sin (- 3 x) - 4 y + x y)

7 (ln (y)) y^{^{'}} - x^{3} y = 0

What is the solution for y^'= 2/3 xsqrt(1-9y^2) ?
The solution for y^'= 2/3 xsqrt(1-9y^2) is y=(sin(x^2+c_{1}))/3