What is the integral of ln(3x-2) ?

The integral of ln(3x-2) is xln(3x-2)-2/3 ln(3x-2)-x+2/3+C

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integral of ln(3x-2)

\int ln (3 x - 2) d x

x ln (3 x - 2) - \frac{2}{3} ln (3 x - 2) - x + \frac{2}{3} + C

Solution steps

\int ln (3 x - 2) d x

Apply u-substitution

: \int ln (u) \frac{1}{3} d u

= \int ln (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int ln (u) d u

Apply Integration By Parts

: u ln (u) - \int 1 d u

= \frac{1}{3} (u ln (u) - \int 1 d u)

\int 1 d u = u

= \frac{1}{3} (u ln (u) - u)

Substitute back

u = 3 x - 2

= \frac{1}{3} ((3 x - 2) ln (3 x - 2) - (3 x - 2))

Simplify

\frac{1}{3} ((3 x - 2) ln (3 x - 2) - (3 x - 2)) : x ln (3 x - 2) - \frac{2}{3} ln (3 x - 2) - x + \frac{2}{3}

= x ln (3 x - 2) - \frac{2}{3} ln (3 x - 2) - x + \frac{2}{3}

Add a constant to the solution

= x ln (3 x - 2) - \frac{2}{3} ln (3 x - 2) - x + \frac{2}{3} + C

\int x^{3} + sin (x) d x

\frac{d}{d x} (\frac{sin ( x )}{x})

(2 x^{2} + 1)^{3} \cdot (x^{2} - 1)

2 x + 4, 2 - 3 x, - x

What is the integral of ln(3x-2) ?
The integral of ln(3x-2) is xln(3x-2)-2/3 ln(3x-2)-x+2/3+C