What is the tangent of f(x)=-4tan(x)-1,\at x=-pi/4 ?

The tangent of f(x)=-4tan(x)-1,\at x=-pi/4 is y=-8x+3-2pi

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tangent of f(x)=-4tan(x)-1,\at x=-pi/4

tangent of

f (x) = - 4 tan (x) - 1, at x = - \frac{π}{4}

y = - 8 x + 3 - 2 π

Solution steps

Find the tangent point:

(- \frac{π}{4}, 3)

Find the slope of

f (x) = - 4 tan (x) - 1 : \frac{df ( x )}{d x} = - 4 sec^{2} (x)

Compute the slope of

f (x) = - 4 tan (x) - 1

x = - \frac{π}{4} : m = - 8

Find the line with slope m=

- 8

and passing through

(- \frac{π}{4}, 3) : y = - 8 x + 3 - 2 π

y = - 8 x + 3 - 2 π

\frac{\partial}{\partial x} (2 y^{6} + 4 y^{8} x^{3})

- \frac{9}{x}

f (x) = x^{3} - 3 x + 1, (3, 19)

\int cos^{15} (x) sin (x) d x

\int \frac{x}{4 x ^{2} - 4 x + 5} d x

What is the tangent of f(x)=-4tan(x)-1,\at x=-pi/4 ?
The tangent of f(x)=-4tan(x)-1,\at x=-pi/4 is y=-8x+3-2pi