What is the solution for (dy)/(dx)+2/x y= 1/(x^4) ?

The solution for (dy)/(dx)+2/x y= 1/(x^4) is y=-1/(x^3)+(c_{1})/(x^2)

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(dy)/(dx)+2/x y= 1/(x^4)

\frac{d y}{d x} + \frac{2}{x} y = \frac{1}{x ^{4}}

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

Solution steps

\frac{d y}{d x} + \frac{2}{x} y = \frac{1}{x ^{4}}

Solve linear ODE:

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

\int - 4 e^{- t} d t

\int \frac{1}{( 3 x - 1 ) ^{2}} d x

\int_{0}^{4} 9 e^{- 2 x} d x

(arcsin (x))^{3}

t \to 0 lim (\frac{1}{t} - \frac{1}{t ^{2} + t})

What is the solution for (dy)/(dx)+2/x y= 1/(x^4) ?
The solution for (dy)/(dx)+2/x y= 1/(x^4) is y=-1/(x^3)+(c_{1})/(x^2)