What is the derivative of (x^2-4/(x-2)) ?

The derivative of (x^2-4/(x-2)) is 1

What is the first derivative of (x^2-4/(x-2)) ?

The first derivative of (x^2-4/(x-2)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 4}{x - 2})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 4}{x - 2})

Simplify

\frac{x ^{2} - 4}{x - 2} : x + 2

= \frac{d}{d x} (x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (2)

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 1 + 0

Simplify

= 1

\frac{d}{d x} (ln (x^{3} + 6 x^{2}))

f (x) = x^{2} - 8 x^{2}

\frac{\partial}{\partial x} (\frac{w ^{T} e ^{- w^{T} x}}{( 1 + e ^{- w^{T} x} ) ^{2}})

\frac{1}{( b ^{2} \cdot ( \frac{1 + x}{b ^{2}} ) )}

x \to 1 - lim (1 - x)

What is the derivative of (x^2-4/(x-2)) ?
The derivative of (x^2-4/(x-2)) is 1
What is the first derivative of (x^2-4/(x-2)) ?
The first derivative of (x^2-4/(x-2)) is 1