What is the integral of (x^3-5x)^5(3x^2-5) ?

The integral of (x^3-5x)^5(3x^2-5) is ((x^3-5x)^6)/6+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^3-5x)^5(3x^2-5)

\int (x^{3} - 5 x)^{5} (3 x^{2} - 5) d x

\frac{( x ^{3} - 5 x ) ^{6}}{6} + C

Solution steps

\int (x^{3} - 5 x)^{5} (3 x^{2} - 5) d x

Apply u-substitution

: \int u^{5} d u

= \int u^{5} d u

Apply the Power Rule

: \frac{u ^{6}}{6}

= \frac{u ^{6}}{6}

Substitute back

u = x^{3} - 5 x

= \frac{( x ^{3} - 5 x ) ^{6}}{6}

Add a constant to the solution

= \frac{( x ^{3} - 5 x ) ^{6}}{6} + C

\frac{d}{d x} ((5 x)^{2})

\frac{20}{s}

y^{^{'}} = 4 y^{2} sin (x)

\frac{\partial}{\partial x} (\frac{2}{x ^{2}})

θ \to 0 lim (\frac{tan ( θ )}{θ})

What is the integral of (x^3-5x)^5(3x^2-5) ?
The integral of (x^3-5x)^5(3x^2-5) is ((x^3-5x)^6)/6+C