What is the limit as x approaches-2 of (x^3-8)/(x+2) ?

The limit as x approaches-2 of (x^3-8)/(x+2) is diverges

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limit as x approaches-2 of (x^3-8)/(x+2)

x \to - 2 lim (\frac{x ^{3} - 8}{x + 2})

diverges

Solution steps

x \to - 2 lim (\frac{x ^{3} - 8}{x + 2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 2 + lim (\frac{x ^{3} - 8}{x + 2}) = - \infty

x \to - 2 - lim (\frac{x ^{3} - 8}{x + 2}) = \infty

= diverges

x \to 2 lim (x + 5)

f (x) = (x^{2} + 3)^{\frac{1}{2}}, at x = 1

\int (1 - \frac{x}{4})^{2} d x

y^{^{'}} = - 2 x y^{3}

x \to \frac{3 π}{2} lim (sec (x))

What is the limit as x approaches-2 of (x^3-8)/(x+2) ?
The limit as x approaches-2 of (x^3-8)/(x+2) is diverges