What is the integral from 0 to pi/4 of 7sec^2(x) ?

The integral from 0 to pi/4 of 7sec^2(x) is 7

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integral from 0 to pi/4 of 7sec^2(x)

\int_{0}^{\frac{π}{4}} 7 sec^{2} (x) d x

7

Solution steps

\int_{0}^{\frac{π}{4}} 7 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{0}^{\frac{π}{4}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= 7 [tan (x)]_{0}^{\frac{π}{4}}

Compute the boundaries:

1

= 7 \cdot 1

Simplify

= 7

\frac{d}{d x} (3 (2 x e^{x} + e^{x} x^{2}))

y^{^{'}} = \frac{y ^{2}}{t ^{3}}

ln (x e^{- 6 x})

\frac{sec ( θ )}{1 + sec ( θ )}

\int \frac{7 x ^{2} + 3 x + 4}{x ^{3} - x} d x

What is the integral from 0 to pi/4 of 7sec^2(x) ?
The integral from 0 to pi/4 of 7sec^2(x) is 7