What is the derivative of f(x)=2x^2-4x ?

The derivative of f(x)=2x^2-4x is 4x-4

What is the first derivative of f(x)=2x^2-4x ?

The first derivative of f(x)=2x^2-4x is 4x-4

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derivative of

f (x) = 2 x^{2} - 4 x

4 x - 4

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

= 4 x - 4

f (x) x^{2} + 8 x - 2

\int_{1}^{10} \frac{1}{x} d x

- arctan (x)

\int \frac{x e ^{5 x}}{( 5 x + 1 ) ^{2}} d x

x \to 0 lim (e^{\frac{∣ x ∣}{x}})

What is the derivative of f(x)=2x^2-4x ?
The derivative of f(x)=2x^2-4x is 4x-4
What is the first derivative of f(x)=2x^2-4x ?
The first derivative of f(x)=2x^2-4x is 4x-4