What is the derivative of x^2+3x+1 ?

The derivative of x^2+3x+1 is 2x+3

What is the first derivative of x^2+3x+1 ?

The first derivative of x^2+3x+1 is 2x+3

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derivative of

x^{2} + 3 x + 1

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 2 x + 3 + 0

Simplify

= 2 x + 3

f (t) = 7 t + 3

\int \frac{1}{x 1 - x ^{2}} d x

f (x) = \frac{1 - 3 x}{6 + x}

x \to - 1 + lim (\frac{∣ x + 1 ∣}{x - 1})

What is the derivative of x^2+3x+1 ?
The derivative of x^2+3x+1 is 2x+3
What is the first derivative of x^2+3x+1 ?
The first derivative of x^2+3x+1 is 2x+3