What is the solution for derivative of f(x^2)=x^4 ?

The solution for derivative of f(x^2)=x^4 is f(x)=(x^3)/5+(c_{1})/(x^2)

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derivative of f(x^2)=x^4

\frac{d}{d x} (f (x^{2})) = x^{4}

f (x) = \frac{x ^{3}}{5} + \frac{c _{1}}{x ^{2}}

Solution steps

\frac{d}{d x} (f (x) (x^{2})) = x^{4}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) x^{2} = \int x^{4} d x

\int x^{4} d x = \frac{x ^{5}}{5} + c_{1}

f (x) x^{2} = \frac{x ^{5}}{5} + c_{1}

Isolate

f (x) : f (x) = \frac{x ^{3}}{5} + \frac{c _{1}}{x ^{2}}

f (x) = \frac{x ^{3}}{5} + \frac{c _{1}}{x ^{2}}

\frac{d ^{2} y}{d θ ^{2}} + y = 0

\int (x^{2} - 2) (x^{3} - 6 x)^{207} d x

x \to 2 lim (3 x^{2})

\frac{\partial}{\partial x} (- x - 6 y)

y = \frac{1}{x}

What is the solution for derivative of f(x^2)=x^4 ?
The solution for derivative of f(x^2)=x^4 is f(x)=(x^3)/5+(c_{1})/(x^2)